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## Homework Statement

On a level road a motorcycle slows down with an acceleration of -3.40 m/s^2. Calculate the value of its acceleration when the road goes up hill 15 degrees.

## Homework Equations

Fnet = MA[/B]

## The Attempt at a Solution

I tried setting up a system of equations and made friction equal.[/B]

**Level road: friction force = ma**

Inclined road: friction + wsin(theta) = ma2

Ma= ma2-wsin(theta)

Ma = ma2 - mgsin(theta)

A = a2 - gsin(theta)

A2 = A + gsin(theta)

A2 = -3.40 + (-9.8)(sin15)

But the answer isn't -5.94, so I don't know what I'm doing wrong. Thanks.

Inclined road: friction + wsin(theta) = ma2

Ma= ma2-wsin(theta)

Ma = ma2 - mgsin(theta)

A = a2 - gsin(theta)

A2 = A + gsin(theta)

A2 = -3.40 + (-9.8)(sin15)

But the answer isn't -5.94, so I don't know what I'm doing wrong. Thanks.