# Projectile Motion Problems

On this page I put together a collection of projectile motion problems to help you understand projectile motion better. The required equations and background reading to solve these problems is given on the

projectile motion page.

I also provide hints and numerical answers for these problems.

Refer to the figure below (along with sign convention shown), for problems 1-7. Use

*g* = 9.8 m/s

^{2}.

For problems 1-6 and 8, ignore air resistance in your calculations.

**Problem # 1**
For

*Δd*_{y} = 0 and for any given

*v*_{o} find

*θ* so that the range (

*Δd*_{x}) is maximum.

Hint and answer
**Problem # 2**
Find the maximum height (

*h*) and range for

*v*_{o} = 10 m/s,

*θ* = 30°, and

*Δd*_{y} = -10 m. What is the flight time?

Hint and answer
**Problem # 3**
Find the maximum height and range for

*v*_{o} = 10 m/s,

*θ* = 30°, and

*Δd*_{y} = 1 m. The displacement

*Δd*_{y} corresponds to the stage of the projectile flight where it is moving downward. What is the flight time?

Hint and answer
**Problem # 4**
Find

*Δd*_{y} for

*v*_{o} = 10 m/s,

*θ* = 30°, and

*Δd*_{x} = 15 m. What is the flight time?

Hint and answer
**Problem # 5**
Find the maximum height and range for

*v*_{o} = 10 m/s, and

*θ* = 90°.

Hint and answer
**Problem # 6**
Find the maximum height and range for

*v*_{o} = 10 m/s,

*θ* = 0, and

*Δd*_{y} = -5 m.

Hint and answer
**Problem # 7**
Find the maximum height and range for

*v*_{o} = 10 m/s,

*θ* = 30°, and

*Δd*_{y} = -10 m. Account for air resistance, with drag coefficient equal to 0.47, projected frontal area equal to 0.01 m

^{2}, density of air equal to 1.2 kg/m

^{3}, and mass of projectile equal to 0.1 kg. Compare this to the answer in problem 2.

Hint and answer
**Problem # 8**
A ball is kicked at an angle

*θ* = 45°. It is intended that the ball lands in the back of a moving truck which has a trunk of length

*L* = 2.5 m. If the initial horizontal distance from the back of the truck to the ball, at the instant of the kick, is

*d*_{o} = 5 m, and the truck moves directly away from the ball at velocity

*V* = 9 m/s (as shown), what is the maximum and minimum velocity

*v*_{o} so that the ball lands in the trunk. Assume that the initial height of the ball is equal to the height of the ball at the instant it begins to enter the trunk.

Hint and answer
The hints and answers for these projectile motion problems will be given next.

**Hints And Numerical Answers For Projectile Motion Problems**
__Hint and answer for Problem # 1__
Referring to the

projectile motion page, set

*v*_{x} =

*v*_{o}cos

*θ* and

*v*_{1y} =

*v*_{o}sin

*θ*. Obtain an explicit expression for time

*t* based on the quantities

*v*_{1y} and

*Δd*_{y}, and find

*θ* so that

*Δd*_{x} is maximum.

Answer:

*θ* = 45°

__Hint and answer for Problem # 2__
Refer to the

projectile motion page. To find maximum height set

*v*_{1y} =

*v*_{o}sin

*θ*. We know that at maximum height there is zero vertical velocity (

*v*_{2y} = 0). There is a specific equation on the

projectile motion page which you can use to solve for the maximum height when

*v*_{2y} = 0. To find the range you first need to find the total time

*t* the projectile is airborne, and then you can use this time to find the range

*Δd*_{x} =

*v*_{x}*t* where

*v*_{x} =

*v*_{o}cos

*θ*.

Answer:

*h* = 1.276 m,

*Δd*_{x} = 17.556 m,

*t* = 2.027 s

__Hint and answer for Problem # 3__
This problem is similar to problem 2 so the hint for it applies here as well. Note that there are two solutions for time

*t* which correspond to

*Δd*_{y} = 1 m. You must choose the largest time

*t* corresponding to the stage of the flight where the projectile is moving downward.

Answer:

*h* = 1.276 m,

*Δd*_{x} = 6.472 m,

*t* = 0.747 s

__Hint and answer for Problem # 4__
Given known

*Δd*_{x} = (

*v*_{o}cos

*θ*)

*t*, with

*v*_{o} and

*θ* known, find

*t* and then use this

*t* to find

*Δd*_{y} using the equation for vertical displacement (

*Δd*_{y}) on the

projectile motion page.

Answer:

*Δd*_{y} = -6.04 m,

*t* = 1.732 s

__Hint and answer for Problem # 5__
This projectile motion problem involves strictly vertical projectile motion, which means there is no horizontal velocity component to consider.

Answer:

*h* = 5.102 m,

*Δd*_{x} = 0

__Hint and answer for Problem # 6__
This projectile motion problem involves initially horizontal projectile motion, which means there is no initial vertical velocity component to consider.

Answer:

*h* = 0,

*Δd*_{x} = 10.102 m

__Hint and answer for Problem # 7__
You need to solve this with numerical methods which accounts for the effects of air resistance. I created a

projectile motion simulator to solve problems like this.

Answer:

*h* = 1.175 m,

*Δd*_{x} = 14.22 m

__Hint and answer for Problem # 8__
When the ball begins to enter the trunk, the horizontal distance

*Δd*_{x} traveled by the ball is given by

*Δd*_{x} = (

*v*_{o}cos

*θ*)

*t*, which is also equal to the distance

*d*_{o}+

*Vt* for minimum

*v*_{o} and

*d*_{o}+

*L*+

*Vt* for maximum

*v*_{o}, where

*t* is the total time. To determine the total time

*t* set

*Δd*_{y} = 0, and solve for

*t*. You can then solve for minimum

*v*_{o} and maximum

*v*_{o}.

Answer: Minimum

*v*_{o} = 15.824 m/s, maximum

*v*_{o} = 17.041 m/s

Projectile motion problems like the ones given above are a good way to test understanding. To see an interesting real-world application of projectile motion go to

The Physics Of Volleyball.

Also, see the problem,

Maximum shot put distance.

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