Projectile Motion Problems

On this page I put together a collection of projectile motion problems to help you understand projectile motion better. The required equations and background reading to solve these problems is given on the projectile motion page.





I also provide hints and numerical answers for these problems.


Refer to the figure below (along with sign convention shown), for problems 1-7. Use g = 9.8 m/s2.

projectile motion problems figure 1

For problems 1-6 and 8, ignore air resistance in your calculations.


Problem # 1

For Δdy = 0 and for any given vo find θ so that the range (Δdx) is maximum.

Hint and answer


Problem # 2

Find the maximum height (h) and range for vo = 10 m/s, θ = 30°, and Δdy = -10 m. What is the flight time?

Hint and answer


Problem # 3

Find the maximum height and range for vo = 10 m/s, θ = 30°, and Δdy = 1 m. The displacement Δdy corresponds to the stage of the projectile flight where it is moving downward. What is the flight time?

Hint and answer


Problem # 4

Find Δdy for vo = 10 m/s, θ = 30°, and Δdx = 15 m. What is the flight time?

Hint and answer


Problem # 5

Find the maximum height and range for vo = 10 m/s, and θ = 90°.

Hint and answer


Problem # 6

Find the maximum height and range for vo = 10 m/s, θ = 0, and Δdy = -5 m.

Hint and answer


Problem # 7

Find the maximum height and range for vo = 10 m/s, θ = 30°, and Δdy = -10 m. Account for air resistance, with drag coefficient equal to 0.47, projected frontal area equal to 0.01 m2, density of air equal to 1.2 kg/m3, and mass of projectile equal to 0.1 kg. Compare this to the answer in problem 2.

Hint and answer


Problem # 8

projectile motion problems figure 2

A ball is kicked at an angle θ = 45°. It is intended that the ball lands in the back of a moving truck which has a trunk of length L = 2.5 m. If the initial horizontal distance from the back of the truck to the ball, at the instant of the kick, is do = 5 m, and the truck moves directly away from the ball at velocity V = 9 m/s (as shown), what is the maximum and minimum velocity vo so that the ball lands in the trunk. Assume that the initial height of the ball is equal to the height of the ball at the instant it begins to enter the trunk.

Hint and answer


The hints and answers for these projectile motion problems will be given next.

Hints And Numerical Answers For Projectile Motion Problems


Hint and answer for Problem # 1

Referring to the projectile motion page, set vx = vocosθ and v1y = vosinθ. Obtain an explicit expression for time t based on the quantities v1y and Δdy, and find θ so that Δdx is maximum.

Answer: θ = 45°


Hint and answer for Problem # 2

Refer to the projectile motion page. To find maximum height set v1y = vosinθ. We know that at maximum height there is zero vertical velocity (v2y = 0). There is a specific equation on the projectile motion page which you can use to solve for the maximum height when v2y = 0. To find the range you first need to find the total time t the projectile is airborne, and then you can use this time to find the range Δdx = vxt where vx = vocosθ.

Answer: h = 1.276 m, Δdx = 17.556 m, t = 2.027 s


Hint and answer for Problem # 3

This problem is similar to problem 2 so the hint for it applies here as well. Note that there are two solutions for time t which correspond to Δdy = 1 m. You must choose the largest time t corresponding to the stage of the flight where the projectile is moving downward.

Answer: h = 1.276 m, Δdx = 6.472 m, t = 0.747 s


Hint and answer for Problem # 4

Given known Δdx = (vocosθ)t, with vo and θ known, find t and then use this t to find Δdy using the equation for vertical displacement (Δdy) on the projectile motion page.

Answer: Δdy = -6.04 m, t = 1.732 s


Hint and answer for Problem # 5

This projectile motion problem involves strictly vertical projectile motion, which means there is no horizontal velocity component to consider.

Answer: h = 5.102 m, Δdx = 0


Hint and answer for Problem # 6

This projectile motion problem involves initially horizontal projectile motion, which means there is no initial vertical velocity component to consider.

Answer: h = 0, Δdx = 10.102 m


Hint and answer for Problem # 7

You need to solve this with numerical methods which accounts for the effects of air resistance. I created a projectile motion simulator to solve problems like this.

Answer: h = 1.175 m, Δdx = 14.22 m


Hint and answer for Problem # 8

When the ball begins to enter the trunk, the horizontal distance Δdx traveled by the ball is given by Δdx = (vocosθ)t, which is also equal to the distance do+Vt for minimum vo and do+L+Vt for maximum vo, where t is the total time. To determine the total time t set Δdy = 0, and solve for t. You can then solve for minimum vo and maximum vo.

Answer: Minimum vo = 15.824 m/s, maximum vo = 17.041 m/s


Projectile motion problems like the ones given above are a good way to test understanding. To see an interesting real-world application of projectile motion go to The Physics Of Volleyball.

Also, see the problem, Maximum shot put distance.


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